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Java Program to Find Smallest Number in an array
Here is a Java program that demonstrates how to find the smallest number in an array:
It then initializes the smallest variable with the maximum possible integer value (Integer.MAX_VALUE).
The method then loops through the array, comparing each element with smallest. If an element is smaller than smallest, the smallest is updated.
At the end, smallest will hold the smallest element of the array.
This approach is simple and efficient in terms of time complexity as it goes through the array once and the time complexity is O(n).
Another way to find smallest number is by using the inbuilt Arrays.sort(arr) method and return the first element of the array, since after sorting the first element is the smallest.
class ArraySmallest
{
public int findSmallest(int[] arr, int n) {
int smallest = Integer.MAX_VALUE;
for (int i = 0; i < n; i++) {
if (arr[i] < smallest) {
smallest = arr[i];
}
}
return smallest;
}
}
public class Main {
public static void main(String[] args) {
ArraySmallest ar=new ArraySmallest();
int[] arr = {1, 14, 2, 16, 10, 20, 5};
int n = arr.length;
int smallest =ar.findSmallest(arr, n);
System.out.println("Smallest element is " + smallest);
}
}
In this program, The findSmallest method takes two arguments; the array, and the length of the array.It then initializes the smallest variable with the maximum possible integer value (Integer.MAX_VALUE).
The method then loops through the array, comparing each element with smallest. If an element is smaller than smallest, the smallest is updated.
At the end, smallest will hold the smallest element of the array.
This approach is simple and efficient in terms of time complexity as it goes through the array once and the time complexity is O(n).
Another way to find smallest number is by using the inbuilt Arrays.sort(arr) method and return the first element of the array, since after sorting the first element is the smallest.
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