Write a python program to sort list with sorted & lambda

Write a python program to sort list with sorted & lambda

Program

The sorted() function is a high-order function because it takes another function as a parameter. Here, we create a lambda function that is then passed as an argument to the sorted() function key parameter. By using a negative index [-1], we are telling the sorted() function to sort the list in descending order.

def myfun():
    list1 = ['Sateesh', 'Kumar', 'Siva']
    a = lambda x: x[-1]
    y = sorted(list1, key=a)
    print(y)
                 
if __name__=="__main__":
    myfun()

Output:

['Siva', 'Sateesh', 'Kumar']

Program

To sort the list in ascending order, we can just change the index to [:1]. See below:

def myfun():
    list1 = ['Sateesh', 'Kumar', 'Siva']
    a = lambda x: x[:1]
    y = sorted(list1, key=a)
    print(y)
                 
if __name__=="__main__":
    myfun()

Output:

['Kumar', 'Sateesh', 'Siva']

Program

Another easy way to sort the list in ascending order would be to use just the sorted() function. By default, it sorts an iterable in ascending order. Since the key parameter is optional, we just leave it out.

def myfun():
    list1 = ['Sateesh', 'Kumar', 'Siva']
    list2 = sorted(list1)
    print(list2)
                 
if __name__=="__main__":
    myfun()

Output:

['Kumar', 'Sateesh', 'Siva']

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